That's right, it is! As before, if we multiply the cubed function by a number a, we can change the stretch of the graph. Step 1: By the Factor Theorem, if \(x=-1\) is a solution to this equation, then \((x+1)\) must be a factor. {\displaystyle y=x^{3}+px,} I'll subtract 20 from Where might I find a copy of the 1983 RPG "Other Suns"? Step 1: Let us evaluate this function between the domain \(x=3\) and \(x=2\). Write an equation with a variable on both sides to represent the situation. Step 2: Identify the \(x\)-intercepts by setting \(y=0\). add a positive 4 here. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. In calculus, this point is called a critical point, and some pre-calculus teachers also use that terminology. As with quadratic functions and linear functions, the y-intercept is the point where x=0. If you want to find the vertex of a quadratic equation, you can either use the vertex formula, or complete the square. Identify your study strength and weaknesses. going to be a parabola. Find the x- and y-intercepts of the cubic function f (x) = (x+4) (2x-1) If f (x) = x^2 - 2x - 24 and g (x) = x^2 - x - 30, find (f - g) (x). This is known as the vertex form of cubic functions. To shift this vertex to the left or to the right, we {"smallUrl":"https:\/\/www.wikihow.com\/images\/thumb\/f\/f0\/Find-the-Vertex-of-a-Quadratic-Equation-Step-1-Version-2.jpg\/v4-460px-Find-the-Vertex-of-a-Quadratic-Equation-Step-1-Version-2.jpg","bigUrl":"\/images\/thumb\/f\/f0\/Find-the-Vertex-of-a-Quadratic-Equation-Step-1-Version-2.jpg\/aid586797-v4-728px-Find-the-Vertex-of-a-Quadratic-Equation-Step-1-Version-2.jpg","smallWidth":460,"smallHeight":345,"bigWidth":728,"bigHeight":546,"licensing":"